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Calculate the energy of an electron in second orbit of an excited hydrogen atom the energy of the electron in the first Bohr orbit the energy of the electron in the Bohr orbit is `-2.18 xx 10^(-11) erg` |
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Answer» We know that `E_(n) = (E_(1))/(n^(2))= (2.18 xx 10^(-11))/((2)^(2))` ` = - 0.545 xx 10^(-11) erg` |
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