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Calculate the energy of photons of radiation whose wavelength is `5000A^(@)`? |
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Answer» `lambda = 5000 A^(@) = 5000 xx 10^(-10)m = 5 xx 10^(-7)m` `c = 3 xx 10^(8)m//sec, h = 6.62 xx 10^(-34)js` `E = (hc)/(lambda) = (6.62 xx 10^(-34) xx 3xx 10^(8))/(5 xx 10^(-7))` `= 3.97 xx 10^(-19)J` |
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