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Calculate the energy released by fission from `2 g` of `.^(235)._(92)U` in `kWh`. Given that the energy released per fission is `200 MeV`. |
Answer» Mass of uranium `= 2g` Energy released per fission `= 200 MeV` `=200xx10^(6)xx1.6xx10^(-19)=3.2xx10^(-11)J` Number of atoms in `2` gram of uranium is `n=(2xx6.023xx10^(23))/(235)=5.125xx10^(21)"atoms"` Total energy released `=`No. of atoms `x` energy released per fission `=5.125xx10^(21)xx3.2xx10^(-11)=16.4xx10^(10)J` `=0.455xx10^(5)Kwh=4.55xx10^(4)Kwh` |
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