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Calculate the energy released per nucleon of the reactant, in the thermonuclear reaction `3_(1)H^(2) to _(2)He^(4)to_(2)He^(4)+_(1)H^(1)+_(0)n^(1)+21.6`MeVA. 21.6 MeVB. 7.2 MeVC. 3.6 MeVD. 1.8 MeV |
| Answer» Correct Answer - C | |