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Calculate the fall in temperature when a gas initially at 72^@C is expanded suddenly to eight times its original volume. (gamma = 5//3) |
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Answer» SOLUTION :`T_1V_1^(gamma-1)=T_2V_2^(gamma-1)` `T_2=T_1((V_1)/V_2)^(gamma-1)` `=345xx1/4=86.25 K` |
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