Calculate the freezing point of an aquteous containing 10.50 g of `MgBr_(2)` in 200 g of water (molar mass of `MgBr_(2)=184 mol^(-1),K_(f) for water=1.86 K kg mol^(-1)`)

Calculate the freezing point of an aquteous containing 10.50 g of `MgB

1.	Calculate the freezing point of an aquteous containing 10.50 g of `MgBr_(2)` in 200 g of water (molar mass of `MgBr_(2)=184 mol^(-1),K_(f) for water=1.86 K kg mol^(-1)`)
Answer» Calculation of depression in freezing point temperature `(DeltaT_(f))` `MgBr_(2)` dissociates in aqueous solution as: `MgBr_(2)overset((aq))toMg^(2)(aq)+2Br^(-)(aq)` `i=3, W_(B)=10.50g, m_(B)-184 g mol^(-1)`, `DeltaT_(f)=ixxK_(f)xxm=(ixxK_(f)xxW_(B))/(M_(B)xxW_(A))` `=(3xx(1.86 K kg mol^(-1))xx(10.50g))/((184 g mol^(-1))xx(0.2 kg))=1.59 K` Calculation of freezing point of solution `T_(f)=T_(f)^(@)-DeltaT_(f)(273-1.59)K=271.41 K`

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Calculate the freezing point of an aquteous containing 10.50 g of `MgBr_(2)` in 200 g of water (molar mass of `MgBr_(2)=184 mol^(-1),K_(f) for water=1.86 K kg mol^(-1)`)

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