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Calculate the frequency `&` energy of a photon of wave length `4000A`. |
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Answer» `(a)` Calculation of frequency : ` lambda=4000Å` `lambda=4000xx10^(-10)m` `because " "v=(C )/(lambda)` `therefore " "v=(3xx10^(8)m//sec)/(4xx10^(-7)m)=0.75xx10^(15)sec^-1` `=7.5 xx10^(14)sec^(-1)` `(b)` Calculation of energy : `E=hv=6.626xx10^(-34)"Joule"xx7.5xx10^(14)sec^(-1)` `=4.96xx10^(-19)`Joule |
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