1.

Calculate the frequency `&` energy of a photon of wave length `4000A`.

Answer» `(a)` Calculation of frequency :
` lambda=4000Å`
`lambda=4000xx10^(-10)m`
`because " "v=(C )/(lambda)`
`therefore " "v=(3xx10^(8)m//sec)/(4xx10^(-7)m)=0.75xx10^(15)sec^-1`
`=7.5 xx10^(14)sec^(-1)`
`(b)` Calculation of energy :
`E=hv=6.626xx10^(-34)"Joule"xx7.5xx10^(14)sec^(-1)`
`=4.96xx10^(-19)`Joule


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