

InterviewSolution
Saved Bookmarks
1. |
Calculate the frequency of light amitted in an electron transition from the sixth to the second orbit of a hydrogen atom .In what region of the specturm does this frequency accur? |
Answer» We know that `v = 3.289 xx 10^(15)((1)/(2^(2)) - (1)/(6^(2)))` `= 3.289 xx 10^(15) cm s^(-1) (0.2222 cm^(-1))` `= 7.31 xx 10^(4) s^(-1)` The line is in the visible specturm of hydrogen it is a part of the balmer series because the electron has a transition from a higher orbit to the second orbit |
|