1.

Calculate the frequency of light amitted in an electron transition from the sixth to the second orbit of a hydrogen atom .In what region of the specturm does this frequency accur?

Answer» We know that
`v = 3.289 xx 10^(15)((1)/(2^(2)) - (1)/(6^(2)))`
`= 3.289 xx 10^(15) cm s^(-1) (0.2222 cm^(-1))`
`= 7.31 xx 10^(4) s^(-1)`
The line is in the visible specturm of hydrogen it is a part of the balmer series because the electron has a transition from a higher orbit to the second orbit


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