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Calculate the frequency of light emitted in an electron transition from the sixth to the second orbit of a hydrogen atom. In what region of the specturm does this frequency occur? |
Answer» Correct Answer - `v=7.3xx10^(14) Hz`, visible spectrum `DeltaE_(6 to 2)=hv rArr v=(3.022xx1.6xx10^(-19))/(6.625xx10^(-34))=7.3xx10^(14) Hz` This frequency lies in visible spectrum. |
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