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Calculate the iongest wavelength transition in the paseches series of `He^(o+)`. |
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Answer» `bar v = R_(H) xx Z6*(2) [(1)/(n_(1)^(2)) - (1)/(n_(2)^(2))]` For He `Z = 2` For paschen series , `n_(1) = 3` For the longest wavelength, `n_(2) = 4` `(1)/(lambda) = 109678 xx (2)^(2) xx [(1)/(3^(2)) - (1)/(4^(2))]` `= 10978 xx 4 xx [(1)/(9) - (1)/(16)]` `= 109678 xx 4 xx (7)/(144)` `or lambda = 4589 Å` |
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