1.

Calculate the kinetic energy of a body of mass 0.1 kg and momentum 20 kg ms^(-1)

Answer»

SOLUTION :Given :P20 kg `MS^(-1),m=0.1 kg `
Kinetic energy `K=(1)/(2)mv^(2)` and
Momentum `p=mv` or `v=(p)/(m)`
Eliminating v,
`K=(1)/(2)mxx((p)/(m))^(2)=(p^(2))/(2m)`
`therefore K=((20)^(2))/(2xx0.1)=2000 J=2xx10^(3)J`


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