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Calculate the length of a seconds' pendulum at a place where g= 9.8 m s^(-2) |
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Answer» Solution :For seconds. PENDULUM T= 2.0 s, G= `9.8 m s^(-2)` From the RELATION `T = 2pi SQRT(l/g)` length of pendulum `l = (gT^2)/(4pi^2)` `therefore l = (9.8 xx (2.0)^2)/(4xx(3.14)^2) = 0.994 m ` |
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