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Calculate the mass of the following: 1//51xx10^(23) molecules of water |
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Answer» Solution :`"MOLECULAR mass of "H_(2)O=18` `"NUMBER of moles"=("Number of MOLECULES of water")/("Avogadro.s number")` `=1.51xx10^(23)//6.023xx10^(23)` `=1//4` `="0.25 moles"` |
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