

InterviewSolution
Saved Bookmarks
1. |
Calculate the mass of urea (NH2CONH2) required in making 2.5 kg of 0.25 molal aqueous solution. |
Answer» 0.25 molal aqueous solution means that Moles of urea = 0.25 mole Mass of solvent (water) = 1 kg = 1000 g Molar mass of urea = 14 + 2 + 12 + 16 + 14 + 2 = 6O g mol-1 0.25 mole of urea = 60 x 0.25 mole = 15 g Total mass of the solution = 1000 + 15 g = 1015 g = 1.015 g Thus, 1.015 kg of solution contain urea = 15 g 2.5 kg of solution will require urea = \(\frac{15}{100}\) x 2.5 kg = 37g |
|