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Calculate the mass of Urea required in making 2.5 Kg of 0.25 molal aqueous solution. |
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Answer» moles of Urea=0.25 Molar mass of Urea=60 Mass of Urea=0.25 x 60=15 g Mass of solvent =1000 g Mass of solution=15+1000 = 1015 g 1015 g of solution has =15 g of Urea Hence 2500 g of aqueous solution has =15/1015 X 2500 g of urea =36.95 g. |
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