1.

Calculate the mass of Urea required in making 2.5 Kg of 0.25 molal aqueous solution. 

Answer»

moles of Urea=0.25 

Molar mass of Urea=60 

Mass of Urea=0.25 x 60=15 g 

Mass of solvent =1000 g 

Mass of solution=15+1000 = 1015 g 

1015 g of solution has =15 g of Urea 

Hence 2500 g of aqueous solution has 

=15/1015 X 2500 g of urea  =36.95 g.



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