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Calculate the molal depression constant of a solvent which has freezing point `16.6^(@)C` and latent heat of fusion `180.75 "J g"^(-1)` :A. 2.68B. 3.86C. 4.68D. 2.86 |
Answer» Correct Answer - B `K_(f)=(RT_(0)^(2))/(1000L)" "T_(0)=273+16.6=289.6K` `=(8.314xx(289.6)^(2))/(1000xx180.75)=3.86`] |
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