1.

Calculate the molal elevation constant of water evaporates at `100^(@)"C"` with the absorption of 536 calories per gm `("R"=2 "cals")`A. `0.519^(@)"C"`B. `0.0519^(@)"C"`C. `1.519^(@)"C"`D. `2.519^(@)"C"`

Answer» Correct Answer - A
Molal elevation constant of the solvent.
`"K"_(b)=("RT"_(b)^(2))/(l_("v")xx100)=(2xx373xx373)/(536xx1000)=0.519^(@)"C"`


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