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Calculate the molality of a solution prepared by dissolving 10.5g of NaCl is 250 g of H_(2)O. |
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Answer» Solution :MOLALITY`(m)=(N(mol))/(w(kg))=((10.5g//58.44" g "mol^(-1)))/((250g//1000g" "kg^(-1)))=0.719" mol "kg^(-1)` We report this molality as 0.719 m NACL solution. |
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