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Calculate the molality of a solution that contains 51.2 g of naphthanlene `(C_(10)H_(18))` in 500 mL of carbon tetrechloride. Density of `C CL_(4)` is 1.60 g/mlA. 0.250 mB. 0.500 mC. 0.840 mD. 1.69 m |
Answer» Correct Answer - b `"Mass of" C CI_(4)(W_(A))="Volume "xx"density "` `=(500mL)xx(1.60 g mL^(-1))=800g =0.8 kg` `"Molality of "C CI_(4)(m)=("No.ofmoles of napthalene")/("Mass of "C CI_(4)"in kg")` ` =((51.2g)//(128 g mol^(-1)))/((0.8 kg))` 0.5 `mol kg^(-1)=0.5 m` |
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