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Calculate the molarity of each of the following solutions: 30g of `Co(NO_(3))_(2)6H_(2)O` in 4.3Lpf solution `30 mL of 0.5 M H_(2)SO_(4)`diluted to 500 mL |
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Answer» Molarity of soluion`=("Mass of solute"//"Molar mass of solute")/("Volume of solution in litres")` Mass ofsolute, `Co(NO_(3))_(2).6H_(2)O=30g` Molar mass of solute, `Co(NO_(3))_(2)6H_(2)O=59+2xx14+6xx16+6xx18=291gmol^(-1)` Volume of solution=4.3L Molarity (M)`=((30g)//(291gmol^(-1)))/((4.3L))=0.024 M` Volume of undiluted `H_(2)SO_(4) "solution" (V_(1))=30mL` Molarity of undiluted `H_(2)SO_(4) "solution" (M_(1))=0.5M` Volume of diluted `H_(2)SO_(4) "solution" (V_(2))=500mL` Molarity of diluted `H_(2)SO_(4)(M_(2))` can be calculated as : `M_(1)V_(2)=M_(2)V_(2)` `M_(2)=(M_(1)V_(1))/V_(2)=((30mL)xx(0.5M))/((500mL))=0.03M` |
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