InterviewSolution
Saved Bookmarks
| 1. |
Calculate the momentum of a particle which has a de Broglie wavelength of `10 nm` |
|
Answer» Correct Answer - A::B `1 J = 1 kg m^(2) s^(2) = 10^(7)erg` `1 eV = 1.60 xx 10^(-19) J` `p = (h)/(lambda) = 6.62 xx 10^(-34)( js)10 xx 10^(-9)(m)` `= 6.626 xx 10^(-26) J s m^(-1)` `= 6.626 xx 10^(-26) kg m s^(-1)` |
|