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Calculate the no of protons, neutron and electron in `._(7)^(14)N^(3-)` ion |
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Answer» No. of protons =atomic number `(Z) = 7` No. of protons `=(A-Z) = 14 - 7 = 7` No. of electrons in an ion `=Z+` magnitude of charge `= 7 +3 = 10` |
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