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Calculate the number of molecule present in16.8 L of gas 'X' at STP. Also determine itsgram molecular weight if theabove sample weighs 26.625 g. |
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Answer» SOLUTION :Volume of the given gas= 16.8 L at STP Number of moles present in that volume = 16.8/22.4 = 0.75 moles Number of MOLECULES in 0.75 moles = `0.75 xx 6.023 xx 10^(23) = 4.52 xx 10^(23)` Weight of 0.75 moles of the gasX = 26.625 g Gram MOLECULAR weight of 'X' = Weight /No. of moles = 26.625/0.75 = 35.5g |
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