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Calculate the number of moles in each of the following. (i) 392 g of sulphuric acid (ii) 44.8 litres of sulphur dioxide at N.T.P. (iii) 6.022xx10^(22)" moles of oxygen" (iv) 8g of calcium |
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Answer» SOLUTION :(i) 392 g of sulphuric acid Molar mass of `H_(2)SO_(4)=2xx1+32+4xx16=98g` `"98 g of sulphuric acid = 1 mole"` 392 g of sulphuric acid = 1 mol `xx(392)/((98g))="4 mol"` (II) 44.8 litres of sulphur dioxide at N.T.P 22.4 litres of sulphur dioxide at N.T.T. = 1 mol 44.8 litres of sulphur dioxide at N.T.P. `=("1 mole")/("(22.4 L)")xx(44.8L)="2.0 mol"` (III) `6.022xx10^(22)" molecules of oxygen"` `6.022xx10^(22)" molecules of oxygen = 1 mol"` `6.022xx10^(22)" molecules of oxygen = 1 mol "xx(6.022xx10^(22))/(6.022xx10^(23))="0.1 mol"` (iv) 8g oc CALCIUM Gram atomic mass of `Ca=40g` `"40 g of calcium= 1 mol"` `"8.0 g of calcium = 1 mol"xx((8.0g))/((40g))="0.2 mol."` |
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