1.

Calculate the number of moles in (i) 27 g Al (ii) 1.51xx10^(23)" molecules of "NH_(4)Cl

Answer»

SOLUTION :(i) 27 g of Al
`"Number of moles"=("Mass")/("ATOMIC mass")`
`"Number of moles in 27 g of Al"=(27)/(27)="1 mole"`
(ii) `1.51xx10^(23)" MOLECULES of "NH_(4)Cl`
`"Number of moles"=("Number of molecules")/("Avogadro.s number")=(1.51xx10^(23))/(6.023xx10^(23))="0.25 moles."`


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