1.

Calculate the number of moles in (i) 81 of Aluminium (ii) 4.6 g of sodium (iii) 5.1 g of ammonia (iv) 90 g of water (v) 2g of NaOH.

Answer»

Solution :`"No of moles"=("Given mass")/("ATOMIC mass")`
(i) `"No. of moles of Aluminium "=(81)/(27)`
`="3 moles of aluminium"`
(ii) `"No. of moles of Sodium"=(4.6)/(23)`
`="0.2 moles of sodium"`
(iii) No. of moles of AMMONIA `=(5.1)/(17)`
= 0.3 moles of ammonia
(IV) No. of moles of Water `=(90)/(18)`
= 5 moles of water
(v) No. of moles of `NaOH=(2)/(40)`
= 0.05 moles of `NaOH`


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