1.

Calculate the number of neutrons in the remaining atoms after the emission of an alpha particle from `._(92)U^(238)` atom.

Answer» Correct Answer - 144
Parent element = `._(92)U^(238)`
On account of emission of an alpha particle, the atomic mass is decreased by 4 units and atomic number by 2 units. So, atomic mass of daughter element = 234
Atomic number of daughter element = 90
Number of neutrons = Atomic mass - Atomic number
`= 234 - 90 = 144`


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