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Calculate the number of neutrons in the remaining atoms after the emission of an alpha particle from `._(92)U^(238)` atom. |
Answer» Correct Answer - 144 Parent element = `._(92)U^(238)` On account of emission of an alpha particle, the atomic mass is decreased by 4 units and atomic number by 2 units. So, atomic mass of daughter element = 234 Atomic number of daughter element = 90 Number of neutrons = Atomic mass - Atomic number `= 234 - 90 = 144` |
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