1.

Calculate the number of water molecule present in one drop of water which weighs 0.18 g.

Answer»

SOLUTION :`"The molecular MASS of water "(H_(2)O)` is 18.
18 g of water molecule = 1 mole.
`therefore"0.18 g of water"=(1)/(18)xx0.18="0.10 mole."`
`"1 mole of water (Avogaro.s number) contains "6.023xx10^(23)" water molecules."`
`therefore 0.01"mole of water contain "(6.023xx10^(23))/(1)xx0.01=6.023xx10^(21)" molecules."`


Discussion

No Comment Found

Related InterviewSolutions