1.

Calculate the % of each element in calcium carbonate. (Atomic mass : C-12, O-16, Ca-40)

Answer»

Solution :`"Calcium carbonate : "CaCO_(3)`
`"Molar mass of "CaCO_(3)=40+12+(16xx3)=100G`
`"% of Calcium"=(40)/(100)xx100=40%`
`"% of CARBON "=(12)/(100)xx100=12%`
`"% of Oxygen"=(48)/(100)xx100=48%`


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