1.

Calculate the % of oxygen in Al_(2)(SO_(4))_(3). ("Atomic mass: "Al-12, O-16, S-32)

Answer»

Solution :`"Aluminum Sulphate "-Al_(2)(SO_(4))_(3)`
`"Molar mass of Aluminium Sulphate"=(27xx2)+(32xx3)+(16xx12)`
`=54+96+192=342g`
`"% of OXYGEN "=(192)/(342)xx100=56.14%`


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