Calculate the osmotic pressure of 0.2 M glucose solution at 300 K. (R

1.	Calculate the osmotic pressure of 0.2 M glucose solution at 300 K. (R = 8.314 J mol K-1)
Answer» Given : Concentration of the solution = C = 0.2 M = 0.2 mol dm^-3 = 0.2 × 10 mol m^-3 Temperature = T= 300 K = 8.314 J mol^-1 K^-1 The osmotic pressure, π is given by, π = CRT = 0.2 × 10³ × 8.314 × 300 = 4.988 × 10⁵ Nm^-2 (or Pa) ∴ Osmotic Pressure = 4.988 × 10⁵Nm^-2

Calculate the osmotic pressure of 0.2 M glucose solution at 300 K. (R = 8.314 J mol K-1)

Answer»

Given :

Concentration of the solution

= C = 0.2 M

= 0.2 mol dm^-3 = 0.2 × 10 mol m^-3

Temperature = T= 300 K

= 8.314 J mol^-1 K^-1

The osmotic pressure, π is given by,

π = CRT

= 0.2 × 10³ × 8.314 × 300

= 4.988 × 10⁵ Nm^-2 (or Pa)

∴ Osmotic Pressure = 4.988 × 10⁵Nm^-2

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Calculate the osmotic pressure of 0.2 M glucose solution at 300 K. (R = 8.314 J mol K-1)

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