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1. |
Calculate the percentage degree of dissociation of an electrolyte `XY_(2)` (Normal molar mass `=164`) in water if the observed molar mass by measuring elevation in boiling point is `65.6`: |
Answer» Correct Answer - `75%` `{:(,XY_(2),hArr,X^(2+),+,2Y^(-)),("Initially",1,,0,,0),("at equilibrium",1-alpha,,alpha,,2alpha):}` Total no. of moles `=1-alpha+alpha+2alpha=1+2alpha` `i=("Normal molar mass")/("Observed molar mass"), (1+2alpha)/(1)=(164)/(65.6)` `therefore alpha=0.75,%alpha=75%` |
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