1.

Calculate the pH of sodium hydroxide solution having the concentration of OH^(-) 0.01m L^(-1).

Answer»

Solution :POH=`-log_(10)[OH^(-)]`
pOH=`-log_(10)[1xx10^(-2)]`
pOH=2
pH+pOH=14
`THEREFORE` pH=14-pH=14-2
pH=12


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