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Calculate the pressure exerted by a column of water of height 0.85m (density of water, rho_(w) = 1000 kg m^(-3)) and kerosene of same height (density of kerosene, rho_(k) = 800kg m^(-3)) |
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Answer» Solution :PRESSURE due to water= `h rho_(w) g = 0.85 m XX 1000kgm^(-3) xx 10 m s^(-2) = 8500`Pa. Pressure due to kerosence = `h rho_(k) g = 0.85 m xx 800kgm^(-3) xx 10 MS^(-2) = 6800` Pa . |
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