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Calculate the radius ratio of `3^(rd) & 5^(th)` orbit of `He^(+)`. `r=0.529xx(n^(2))/(Z) Å` At. Number of of He `=2` |
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Answer» `therefore " "r^(3) = 0.529xx((3)^(2))/(2)=0.529xx(9)/(2)` `r^(5) = 0.529xx((5)^(2))/(2)=0.529xx(25)/(2)` Therefore `(r_(3))/(r_(s))=(0.529xx (3)^(2)/(2))/(0.529xx(5)^(2)/(2))` `(r_(3))/(r_(s))=(9)/(25)` |
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