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Calculate the ratio of the wavelength of the first and the nltimate line of the ballmer of `Li^(2+)` ? |
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Answer» Wavelength of the first line of the balmer series `n_(1) = 2 and n_(2) = 3` `bar v _(1)= RZ^(2)[(1)/(2^(2)) - (1)/(3^(2))] = ( 5 xx 5R)/(36) = (5R)/(4)` :. Wavelength of the first line of the bakmer series `= (4)/(5R)` Wavelength of alitimate line (limiting line) of the balmer series `bar v _(2) = RZ^(2)[(1)/(2^(2)) - (1)/(oo)] = (9R)/(4)` Wavelength of the altimate line of the balmer series `= (4)/(9R)` `:. Ratio = (9)/(5)` |
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