1.

Calculate the % relative abundance of B-10 and B-11, if its average atomic mass is 10.804 amu.

Answer»

Solution :Average ATOMIC mass of Boron = 10.804 amu.
`%" relative abundance of "B-10=?`
`%" relative abundance of "B-11=?`
Let the FRACTION of relative abundance of `B-10=x`
Let the fraction of relative abundance of `B-11=y`
`x+y=1`
`y=1-x`
`"Relative abundance"=x(10)+(1-x)(11)=10.804amu`
`RARR 10x+11-11x="10.804 amu"`
`11-x="10.804 amu"`
`-x=10.804-11`
`-x=-0.196`
`x=0.196`
`x=%" abundance of "B-10=0.196xx100=19.6%`
`y=%" abundance of "B-11=100-19.6=80.4%`
Percentage abundance of `B - 10 = 19.6%`
Percentage abundance of `B-11=80.4%`


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