1.

Calculate the resistance of a metal wire of length 2 m and area of cross section 1·55 xx 10^(-6) m^(2), if the resistivity of the metal be 2·8 xx 10^(-8) Omega m ?

Answer»

SOLUTION :`R=(rhol)/(A)`
`=(2.8xx10^(-8)xx2)/(1.55xx10^(-6))`
`=(2.8xx2xx10^(-8-(-6)))/(1.55)`
`=(2.8xx2)/(1.55)xx10^(-2)=0.036 OMEGA`


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