1.

Calculate the resistivity of a material of a wire 10 m long. 0.4 mm in diameter and having a resistance of 2.0Omega.

Answer»

Solution :`L=10m" , "d=0.4mm=0.4xx10^(-3)m`
`r=0.2xx10^(-3)m`
`R=20Omega`
Resistivity (or) specific resistance of a material
`RHO=(RA)/(l)=(Rxxpir^(2))/(l)`
`=(20xx3.14xx(0.2xx10^(-3))^(2))/(10)`
`=6.28xx0.04xx10^(-6)`
`rho=2.513xx10^(-8)OMEGAM`


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