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Calculate the shortest wavelength in H spectrum of Lyman series, when `R_(H) = 109677 cm^(-1)`. |
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Answer» For lyman series `n_(1) = 1` For shortest `lambda `of Lyman series difference in two levels showing transition should be maximum (i.e.`n_(2) = prop` `:. (1)/(lambda) = R_(H) [(1)/(1^(2)) - (1)/(2^(2))] = 109678` `lambda = 911.7 xx 10^(-8) cm = 911.7 Å` For shortest `lambda `of Lyman series difference in two levels showing transition should be maximum (i.e.`n_(2) = 2` `:. (1)/(lambda) = R_(H) [(1)/(1^(2)) - (1)/(2^(2))] = 109678 xx (3)/(4)` `lambda = 1215.67 xx 10^(-8) cm = 1215.67 Å` |
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