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| 1. |
Calculate the standard enthalpy of formation of CH_(3)OH (I) from the following data: CH_(3)OH (I) + 3//2O_(2) (g) rarr CO_(2) (g) + 2H_(2)O(I) , Delta_(c ) H^(theta) = - 726kJ mol^(-1) C(g) + O_(2)(g) rarr CO_(2) (g), Delta_(f) H^(theta) = - 393 kJ mol^(-1) H_(2)(g) + 1//2O_(2) (g) rarr H_(2)O (I), Delta_(f) H^(ө) - 286kJ mol^(-1) |
| Answer» SOLUTION :`-239 KJ MOL^(-1)` | |