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Calculate the time taken to decay `100` percent of a radioactive sample in terms of (a) half- life T and (b) mean-life `T_(av)` |
Answer» We know that `N=N_(0) e^(_lambda t)`, where `lambda =((In 2)/(T)) =(1)/(T_(av))` Here, `N=(1-eta)N_(0)` ` (1-eta)N_(0)=N_(0) e^(-lambda t)` `t=(1)/(lambda)1n|(1)/((1-eta))|` (a) Thus, `t=(T)/(1n2)[1n|(1)/(1-eta)|]=(T)/(0693)In|(1)/(1- eta)|` `t=T_(av) In|(1)/(1-eta)|`. |
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