Calculate the total energy released if `1.0 kg` of `.^(235)U` undergoes fission, taking the disintergration energy per event to be `Q=208 MeV` (a more accurate value than the estimate given previously).

Calculate the total energy released if `1.0 kg` of `.^(235)U` undergoe

1.	Calculate the total energy released if `1.0 kg` of `.^(235)U` undergoes fission, taking the disintergration energy per event to be `Q=208 MeV` (a more accurate value than the estimate given previously).
Answer» We need to know the number of nuclei in `1.00 kg` of uranium. Because `A=235`, the number of nuclei is `N=((6.02 xx 10^(23) "nuclei mol"^(-1))/(235 g mol^(-1))) (1.00 xx 10^(3) g)` `=2.56 xx10^(24) nuclei` Hence, the disintergration energy is ` E=nQ =(2,56 xx 10^(24) "nuclei") (("208 89MeV")/("nucleus"))` Because `1 MeV` is equivalent to `4. 45 xx 10^(20) kWh, E=2.3.7xx10^(7) kWh`. This is enough energy to keep a `100 W` light buth burning for about `30000 years`.

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Calculate the total energy released if `1.0 kg` of `.^(235)U` undergoes fission, taking the disintergration energy per event to be `Q=208 MeV` (a more accurate value than the estimate given previously).

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