1.

Calculate the total number of electrons present in 1.6 g of methane.

Answer»

Solution :(i) Molar MASS of METHANE `(CH_(4))=12+4xx1=16g`
16 g of methane contain molecules `=6.022xx10^(23)`
`"1.6 g of methane contain molecule"=(6.022xx10^(23))/((16g))xx(1.6g)=6.022xx10^(21)" molecules."`
(ii) Numberof electrons in `6.022xx10^(22)` molecules of methane
1 molecule of methane contains electrons `=6+4=10`
`6.022xx10^(22)` molecules of methane contain electrons
`=6.022xx10^(22)xx10=10=6.022xx10^(23)`


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