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Calculate the uncertainty in the position of a particle when the uncertaintly in momentum it: (a). `1xx10^(-3)g" cm "sec^(-1)` (b) zero. |
Answer» (a). Given, `DeltaP=1xx10^(-3)g" cm "sec^(-1)` `h=6.62xx10^(-27)erg-sec` `pi=3.142` According to uncertainty principle, `Deltax*Deltap ge (h)/(4pi)` So, `Delta ge (h)/(4pi)*(1)/(Deltap)ge (6.62xx10^(-27))/(4xx3.142)xx(1)/(10^(-3))` `=0.527xx10^(-24)cm` (b). When the value of `Deltap=0`, the value of `Deltax` will be infinity. |
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