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Calculate the volume of 80% (by mass) of `H_(2)SO_(4)` (density=1.8 g/mL) reqiored tp [reare 1 litre of 0.2 M `H_(2)SO_(4)`. |
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Answer» Correct Answer - 13.61 mL Step I. Calculation of mass of `H_(2)SO_(4)` `"Molarity of acid (M)"=0.2 M=0.2"mol L"^(-1), "Volume os solution"=1 L` Molar mass of acid = 98 g `mol^(-1)` `"Molarity"=("Mass/Molar mass")/("Volume of solution in Litres")` `(0.2" mol L"^(-1))=W/((98" g mol"^(-1))xx(1L))` `1=(0.2" mol L"^(-1))xx(98" g mol"^(-1))(1L)=19.6 g`. step II. Calculation of volume os 80% `H_(2)SO_(2)` `"Volume of pure"H_(2)SO_(4)=("Mass")/("density")=((19.6g))/((1.8" g mol"^(-1)))=10.89 mL` `"Volume of 80% "H_(2)SO_(4)=(10.89mL)xx100/80=13.61 mL` |
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