1.

Calculate the weight of Glucose required to prepare 500ml of 0.1 M solution.

Answer» Molarity = 0.1, Molecular weight of glucose = 180, Volume of solution = 500 ml
Weight of solute `=("Molarity "xx" Gram molecular weight of solute "xx" vol of solin ml")/(1000)`
Weight of solute `=(0.1xx180xx500)/(1000)=9" g ":." Weight of glucose"=9" g"`


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