1.

Calculate the weight of sodium bicarbonate to be dissociated to give 0.56 L of CO_(2) gas.

Answer»

SOLUTION :`{:(2NaHCO_(3) toNaCO+HO+CO),("2 moles""1 mole"):}`
GMW of `NaHCO_(3)` = 84 g
1 mole of `CO_(2)` occupies22.4 L
`22 4" of " CO_(2)` is produced from` 2 xx 84" g of "NaHCO_(3)`
` 0.56 " L of "CO_(2)` is produced from `(0.56 xx 2 84)/(22.4) xx 4.2` g


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