1.

Calculate the weight of zinc required for the liberation of 10 g of hydrogen gas on reaction with H_(2)SO_(4).

Answer»

Solution :`{:(Zn+H_(2)SO_(4) toZnSO_(4) +H_(2)),("1 MOLE""1 mole"):}`
Atomic WEIGHT of zinc is ` 65.5`
1 mole of HYDROGEN = 2 g of hydrogen
10 g of hydrogen = `10/2 = 5` moles
1 mole of `H_(2)` gas is produced FROM1 mole of zinc
5 moles of `H_(2)` gas are produced from 5 molesof zinc.
1 mole of zinc = 65.5g
5 mole of zinc = ` 65.5 xx 5 = 327. 5 ` g


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