1.

Calculate the work required to be done to stop a car of 1500 kg moving at a velocity of 60kmh^(-1).

Answer»


Solution :Here, `m=1500kg`,
`v=60kmh^(-1)=60xx(5)/(18)MS^(-1)=(50)/(3)ms^(-1)`, findla velocity is ZERO.
`THEREFORE` Work REQUIRED to stop the car
= change in K.E. of the car
`=(1)/(2)mv^(2)-(1)/(2)m(0)^(2)`
`=(1)/(2)mv^(2)`
`=(1)/(2)xx1500xx((50)/(3))^(2)J`
`=(1)/(2)xx1500xx(50)/(3)xx(50)/(3)J`
`~~208333.3J`


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